6x^2+12x-228=0

Solution for 6x^2+12x-228=0 equation:

6x^2+12x-228=0

a = 6; b = 12; c = -228;
Δ = b2-4ac
Δ = 122-4·6·(-228)
Δ = 5616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5616}=\sqrt{144*39}=\sqrt{144}*\sqrt{39}=12\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12\sqrt{39}}{2*6}=\frac{-12-12\sqrt{39}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12\sqrt{39}}{2*6}=\frac{-12+12\sqrt{39}}{12}
$